a gun converts 200J of
stored energy into kinetic energy of the 0.02kg bullet. What is the speed of
the bullet as it leaves the gun? If the gun is fired straight up, how high will
the bullet go?
a)200J=1/2 massbullet*velocity^2, v=sqrt(400/0.02kg)=141.4m/s
b)m*g*h= (0.02kg)(9.8m/s^2)h=200J h=1020.4m
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