Time remaining:

# A car can brake to a stop from 60mph in 2.6 seconds. If the car has a weight of

label Physics
account_circle Unassigned
schedule 0 Hours
account_balance_wallet \$5

A car can brake to a stop from 60mph in 2.6 seconds. If the car has a weight of 3225 ibs, what force in Newton's acts on the car.

I got F= -15122.3N is that correct?

Nov 17th, 2017

F=ma, vt=v0+at, a=(vt-v0)/t=(0-60mph)/2.6s=-23.1m/s^2

3225 lbs=1462.84 kg

thus F=1462.84kg*(-23.1m/s^2)=-63.3N

Apr 26th, 2015

I solved for acceleration by using

a= (V^2 - V^1)/t
a= (0-88ft/sec)/2.6 sec
a= -10.316 m/s^2
-10.32N  then solved for force by using

: 3225 lbs * (1 kg / 2.2 lbs) = 1465.91 kg
Thus,
F = 1465.91 kg * -10.316 m/s^2
F = -15122.3 N

What went wrong???

Apr 26th, 2015

F=ma, vt=v0+at, a=(vt-v0)/t=(0-26.8m/s)/2.6s=-10.3m/s^2

You are right, I am wrong :(

I forgot to convert mph to m/s

don't learn from me

the method you are using is also correct

good job, thumbs up!

Apr 26th, 2015

...
Nov 17th, 2017
...
Nov 17th, 2017
Nov 18th, 2017
check_circle