Time remaining:
Homework help for intro to stats

Statistics
Tutor: None Selected Time limit: 0 Hours

Let x1x2, . . . , x100 denote the actual net weights (in pounds) of 100 randomly selected bags of fertilizer. Suppose that the weight of a randomly selected bag has a distribution with mean 50 lb and variance 1 lb2. Let  be the sample mean weight (n = 100).

(a) What is the probability that the sample mean is between 49.85 lb and 50.15 lb? (Round the answer to four decimal places.)
P(49.85 ≤  ≤ 50.15) =  

(b) What is the probability that the sample mean is less than 50 lb?
 
Apr 26th, 2015

a)  Z  for 50.15 lbs =  50.15 - 50 / (1/√100) = 0.15 / 0.1 = 1.5

P(Z=1.5) = 0.9332

Z for 49.85 =  49.85 - 50 / (1/√100) = -0.15 / 0.1 = -1.5

P(Z=-1.5) = 0.0668

P(49.85 <_Z< 50.15) = 0.9332 - 0.0668 = 0.8664

b) 0.5000

Apr 26th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Apr 26th, 2015
...
Apr 26th, 2015
Dec 3rd, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer