A 124 g ice cube at 0◦C is placed in 777 g of
water at 53◦C. What is the final temperature
of the mixture? The specific heat of water is
4186 J/kg ·
◦C and its latent heat of fusion is
3.33 × 105
Answer in units of ◦C.
Let final temp be T.
Heat gained by ice=m(heat of fusion +CdT)
Heal lost by water=mCdT
Heat lost by ice=heat gained by water
0.124[3.33*105 +4186*(T-0)] =0.777*4186*(53-T)
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