One liter of water at 35◦C is used to make iced
How much ice at 0 ◦C must be added to
lower the temperature of the tea to 12 ◦C?
The specific heat of water is 1 cal/g ·
◦ C and
latent heat of ice is 79.7 cal/g.
Answer in units of g.
Let "x" be weight of ice added
Heat required to be absorbed for taking temperature of water from 35 to 12 decC = Heat required to take temperature of ice from 0 to 12 degC
1000*1*(35-12) = x*1*12 + x*79.7
Solving for x we get x = 250.82 gms (ANSWER)
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