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Find the specific heat of the metal

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A 0.0409 kg ingot of metal is heated to 233◦C and then is dropped into a beaker containing 0.38 kg of water initially at 19◦C. If the final equilibrium state of the mixed system is 21.4 ◦C, find the specific heat of the metal. The specific heat of water is 4186 J/kg · ◦ C. Answer in units of J/kg · ◦ C.

Apr 26th, 2015

qmetal = qwater

(mass) (Δt) (Cp) = (mass) (Δt) (Cp)

0.0409 * (233-21.4)*x = 0.38 * 4186 * (21.4 -19)

x = 441.11 J/kg · ◦ C. (ANSWER)


Important assumption is that there is no loss of heat to environment.

Apr 26th, 2015

Please best the solution.. :)

Apr 26th, 2015

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Apr 26th, 2015
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