##### chemistry help on limiting reagents

 Chemistry Tutor: None Selected Time limit: 1 Day

153 grams of ammonia and 325 grams of oxygen were reacted according to the following equation:

4NH3 + 5O2 --> 4NO + 6H2O

a) what is the limiting reagent?

b) how many grams of each are produced?

c) what is the percent yield assuming that 204 grams of water were actually produced?

d) compare the total masses of reactant to the total mass of products. what law does this prove?

Apr 26th, 2015

a. We divide the grams by the weights of the molecules to get the number of oxygen and ammonia molecules. Using a periodic table, 02 weighs 2*16=32. NH3 weighs 14*3*1=42. 325/32=10.156 ; 153/42=3.642. They occur at a ratio of 5/4 in the reaction. Thus we divide accordingly: 10.156/5=2.0312  , 3.642/4=.911 . Thus ammonia is the limiting reagent. b. Thus we get .911*4 (NO) and .911*6(H20) . Including the weight of the molecules yields weights in grams. Using periodic table, we have .911*4(14+16) and .911*6(2+16). That is 109.32 and 98.388

c. 204/(153+325)=42.7%

d. Conservation of mass.

Apr 26th, 2015

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Apr 26th, 2015
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Apr 26th, 2015
Dec 2nd, 2016
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