Description
Explanation & Answer
DATA:
pH = 2
Concentration of OH- =?
Concentration of Fe3+ = ?
Mass of Fe3+ in g/L =?
SOLUTION:
pH + pOH = 14
pOH= 14 –pH
pOH= 14 -2
pOH = 12
pOH = -log[OH-]
[OH-] = antilog – 12
[OH-] = 1*10-12 mol/L
Fe(OH)3 = Fe3++ 3OH-
3 OH- = 1Fe(OH)3
3 mol of OH- are liberated by 1 mol of Fe(OH)3
1*10-12 mol of OH- are liberated by( 1*1*10-12)/3
= 3.333*10-13 mol of Fe(OH)3 /L
1Fe(OH)3
= 1Fe3+
1mol of Fe(OH)3 liberates 1 mol of Fe3+
3.333*10-13 mol of Fe(OH)3 liberates 1*3.333*10-13
=3.333*10-13 mol of Fe3+/L
Mass of Fe3+ = mol of Fe3+ * Atomic mass of iron
= 3.333*10-13 mol/L * 55.845g/ mol
= 1.861*10-11 g/L
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