easy chem question! will best answer! thanks :)

Chemistry
Tutor: None Selected Time limit: 1 Day

Apr 25th, 2015

DATA:

pH = 2

Concentration of OH- =?

Concentration of Fe3+ = ?

Mass of Fe3+ in g/L =?

SOLUTION:

pH + pOH = 14

pOH= 14 –pH

pOH= 14 -2

pOH = 12

pOH = -log[OH-]

[OH-] = antilog – 12

[OH-] = 1*10-12 mol/L

  Fe(OH)3  =  Fe3++ 3OH-

          3 OH- = 1Fe(OH)3 

3 mol of OH- are liberated by 1 mol of Fe(OH)3 

1*10-12 mol of OH- are liberated by( 1*1*10-12)/3

  = 3.333*10-13 mol of Fe(OH)3 /L

           1Fe(OH)3  = 1Fe3+

1mol of Fe(OH)3  liberates 1 mol of Fe3+

3.333*10-13 mol of Fe(OH)3  liberates 1*3.333*10-13

  =3.333*10-13 mol of Fe3+/L

Mass of Fe3+ = mol of Fe3+ * Atomic mass of iron

  = 3.333*10-13 mol/L * 55.845g/ mol

  = 1.861*10-11 g/L


Apr 26th, 2015

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