In the xy-plane, a certain triangle has an area of 4. If two of the vertices have coordinates (5,6) and (5,8),respectively, what is one possible value for the x-coordinate of the third vertex?
The answer is 1 or 9 but I'm not sure how they arrived at this answer.
The area of the triangle is 4 = Area= 1/2bh
4=1/2*2*h...........base is 2 points (5,6) and (5,8) y has gone up by 2 points
.h is the height of the triangle , so x goes 4 points either way
so the points on the x coordinate will be either be x= 5-4=1 or x= 5+4=9
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