Let the number of quarters = x number of dimes = y Since total has 25 coins, so x+y = 25 ...........Equation (1) 1 quarter = 25 cents...so x quarters = 25*x cents 1 dime = 10 cents.....so y dimes = 10*y cents $3.55 = 3.55 * 100 = 355 cents Since the total value is $3.55 or 355 cents Therefore, 25x+10y = 355.........Equation (2) Solving equation (2) 5*5x + 5*2y = 5*71 => 5(5x+2y) = 5(71) => 5x+2y=71.........Equation (3) From Equation(1) y = 25-x Substituting the value of y in Equation(3) 5x + 2y = 71 => 5x + 2(25-x) = 71 => 5x + 50 - 2x = 71 => 3x = 21 => x = 7 Therefore, No. of Quarters = 24 As, y = 25 -x => y = 25-7=18 Number of dimes = 18, quarters=24 Hence solved