##### chemistry help on decomposition?

label Chemistry
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Silver (i) carbonate was decomposed by heating 948 ml of CO2 gas, collected over water 19.0 celsius and a pressure of 748.6 mmHG.

A) write a balanced equation for this reaction

b) calculate how many grams of  carbon dioxide were collected?

c) assuming all the silver (i) carbonate decomposed, what mass of silver (i) carbonate did you start with?

please explain, i really dont understand the steps to this problem! thank you!

Oct 22nd, 2017

A) Ag2CO3 = Ag2O + CO2

b)  one mole of CO2 = 22.4L

mole of CO2 produced =  0.948/22.4 = 0.042 mol

mass = 0.042 x molecular weight of CO2 = 0.042 x 44 = 1.848 g

C)                                 Ag2CO3 = Ag2O + CO2

initial mole                      x                  0             0

After decomposition         0                   x             x

Apr 26th, 2015

Regarding any doubt plz let me know..

I will explain

Apr 26th, 2015

can you please explain part C again? how do i know the mass of the silver (i) carbonate that i started with?

Apr 27th, 2015

ok.. you got   0.042 mol of CO2 = x

X= 0.042 that will be mole of silver (i) carbonate

Gram of silver (i) carbonate = 0.042 * molecular weight of silver (i) carbonate

= 0.042 *275.74 = 11.58 g

Apr 27th, 2015

I hope you understood

Apr 27th, 2015

okay thank you for explaining!

Apr 27th, 2015

welcome here

Apr 27th, 2015

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Oct 22nd, 2017
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Oct 22nd, 2017
Oct 22nd, 2017
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