Ben had twice as many nickels as dimes. Altogether, Ben had $4.20. How many nickels and how many dimes did Ben have?

Let n = number of nickels

Let d = number of dimes

Then, n = 2d

and,

5n + 10d = 420

substitute n for 2d

5(2d) + 10d = 420

10d + 10d = 420

20d = 420

d = 21

n = 2(21) = 42

Therefore, Ben had 42 nickels and 21 dimes

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