Ben had twice as many nickels as dimes. Altogether, Ben had $4.20. How many nickels and how many dimes did Ben have?

Let number of dimes be d

Let number of nickels be n

Ben had twice as many nickels as dimes.

n = 2d ---(1)

1 dime = 0.1 $

1 nickel = 0.5 dime = 0.05$

Ben had $4.20.

0.05n + 0.1d = 4.2 ---(2)

Substitute n from equation (1) into equation (2)

0.05*2d + 0.1d = 4.2

0.1d + 0.1d = 4.2

0.2d = 4.2

d = 4.2/0.2 = 42/2 = 21

Substitute value of d in equation (1)

n = 2*21 = 42

So Ben had 21 dimes and 42 nickels.

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