Ben had twice as many nickels as dimes. Altogether, Ben had $4.20. How many nickels and how many dimes did Ben have?
Let number of dimes be d
Let number of nickels be n
Ben had twice as many nickels as dimes.
n = 2d ---(1)
1 dime = 0.1 $
1 nickel = 0.5 dime = 0.05$
Ben had $4.20.
0.05n + 0.1d = 4.2 ---(2)
Substitute n from equation (1) into equation (2)
0.05*2d + 0.1d = 4.2
0.1d + 0.1d = 4.2
0.2d = 4.2
d = 4.2/0.2 = 42/2 = 21
Substitute value of d in equation (1)
n = 2*21 = 42
So Ben had 21 dimes and 42 nickels.
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