logb3 of (x+19)(x+13) = 3

Then,

(x+19)(x+13) = 3^3 = 27

x^2 + 32x + 247 = 27

x^2 + 32x + 220 = 0

(x+22)(x+10) = 0

BUT x cannot = -22 since it would create the log of a negative number which is impossible

So, the only acceptable answer is

x = -10

You were correct.

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