sec (3x/2) 2=0

can you retype the question

is it sec (3x/2)-2 =0 ?

No. It's sec(3x/2) +2=0

if it is sec(3x/2)-2 = 0

then we have

cos 3x/2 = 1/2

3x/2 = 2k*pi+pi/3

x = 4kpi/3+2pi/9

or 3x/2 = 2kpi-pi/3

x = 4kpi/3-2pi/9

for x in [0,2pi]

x = 2pi/9,

or

x = 4pi/3-2/9 pi = 10/9 pi

x = 14pi/9,

sec(3x/2)+2 = 0

cos (3x/2)= -1/2

3x/2 = 2npi+ 4/3 pi

x = 4npi/3 +8/9 pi

3x/2 = 2npi - 4/3 pi

x = 4npi/3 -8/9 pi

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