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Precalculus homework help

Calculus
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sec (3x/2) 2=0

Apr 27th, 2015

can you retype the question 

is it sec (3x/2)-2 =0 ?

Apr 27th, 2015

No. It's sec(3x/2) +2=0

Apr 27th, 2015

if it is sec(3x/2)-2 = 0 

then we have 

cos 3x/2 = 1/2 

3x/2 = 2k*pi+pi/3

x = 4kpi/3+2pi/9

 or 3x/2 = 2kpi-pi/3

x = 4kpi/3-2pi/9

for x in [0,2pi] 

x = 2pi/9, 

or 

x = 4pi/3-2/9 pi = 10/9 pi 

or 

x = 14pi/9, 

 

Apr 27th, 2015

sec(3x/2)+2 = 0

cos (3x/2)= -1/2

3x/2 = 2npi+ 4/3 pi 

x = 4npi/3 +8/9 pi 

or 

3x/2 = 2npi - 4/3 pi 

x = 4npi/3 -8/9 pi 

 

Apr 27th, 2015

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Apr 27th, 2015
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