(f o g)(x) = f ( g(x))

= f(5/x )

replace x as 5/x in f(x) that is in 6/(x-7)

thus,

= 6/ (5/x) - 7

= 6 x / (5 -7x).................................................

(f o g)(x) = 6 x / (5 -7x).....................................ANSWER

f(x) and g(x) is defined for all values except at x = 1/7 and x= 0

so answer is A

DOMAIN OF (f o g)(x) = x : x not equal to 1/7 ,0

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