Calculate the wavelength, in nm, of the light emitted when a Be^3+ ion makes a transition from the n=5 to the n=2 state.
E = (4.98 eV) [1/nf2 - 1/ni2]
E=4.98(1/4 -1/25 )
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Did you have a typo in the 5th line? is it suppose to be wavelength= 1.18665 Be^3+ nm ?
no it is calculation by using formula E=hc/wavelength
h=6.626 x 10-34 J s c=3.0 x 108m/s (the speed of light in a vacuum) E=1.045 ev
i put this in ans mistakenly : wavelength=E=hc/wavelength
ok you get it?
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