General Chemistry help

Chemistry
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Calculate the wavelength, in nm, of the light emitted when a Be^3+ ion makes a transition from the n=5 to the n=2 state.

Apr 27th, 2015

E = (4.98 eV) [1/nf2 - 1/ni2]

E=4.98(1/4  -1/25  )

E=1.045 ev

wavelength=E=hc/wavelength

wavelength=1.1865e+3 nm

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Apr 27th, 2015

Did you have a typo in the 5th line? is it suppose to be wavelength= 1.18665 Be^3+ nm ?

Apr 27th, 2015

no it is calculation by using formula E=hc/wavelength

h=6.626 x 10-34 J s                 c=3.0 x 108m/s  (the speed of light in a vacuum)    E=1.045 ev

i put this in ans mistakenly : wavelength=E=hc/wavelength

ok you get it?

Apr 27th, 2015

yesss! Thank you

Apr 27th, 2015

you are welcome, you contact me for help any time , It's honour for me to assist you on your problems.

Apr 27th, 2015

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