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Algebra
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Apr 27th, 2015

standard form of circle is
             (x−h)^2+(y−k)^2=r^2
             here (h,k) is the centre and r is the radius

the centre of the circle is the midpoint of diameter...

since the diameter points are given Apply the Midpoint Formula,to find the centre

    centre of circle= centre of the two points (9,2) and (-1,4)

       centre of circle= ((9+ -1)/2,  (2+ 4)/2)

                               = (4, 3).........

    radius = distance between centre and one of the cordinates through which circle passes

            = distance between (4, 3) and (9,2)

             = (9-4)^2+ (3-2)^2

              = 26......................

    now  standard form of circle is
      (x−h)^2+(y−k)^2=r^2
      

    (x- 4)^2 + ( y- 3 )^2 =  (√26)^2

    (x- 4)^2 + ( y- 3 )^2 =  26............................................................ANSWER


    hope you understand..please message if you have any doubts..thank you



Apr 27th, 2015

(x- 4)^2 + ( y- 3 )^2 =  26....................................answer  (square root not there..i typed wrongly in previous submit)



Apr 27th, 2015

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