The laser in an audio compact disk player uses light with a wavelength of 7.80x10^2 nm.
(i)What is the frequency, in s^-1 of the light?
(ii)What is the wavenumber, in cm^-1, of the light?
(iii)What is the energy, in J, of a single photon of this light ?
(iv)If an object absorbs a total of 8.85 x 10^3 J of this light, how many photons of this light were absorbed?
so you have 7.80x10^2 nm. = (7.80x10^2) x 10^-9 metres
(i)v = f*lamda
f = v/lamda
f = 3.00 x 10^8 x (7.80x10^2) x 10^-9
f =0.0234 s^-1 = .0243Hz
(ii)Wavenumber is 1/wavelength..
wavenumber is 1.28*10^8 cm^-1
(iii)The Energy in J for a photon of light
(iiii)Is E= hf where h is Planck’s constant (6.626 *10^-34)Js and f is .0234 s^-1
Their answer very clear thank you!!
But what is (iii)?
E = hv
(6.626 x 10¯34 J s) (.0243Hz )
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