Time remaining:
find velocity and time equation

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A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajectory is just its weight, so its centripetal acceleration is about  9.81 m/s2 (the acceleration due to gravity near the earth's surface). If the earth's radius is about 6380 km, how fast must the satellite be moving? How long will it take for the satellite to complete one trip around the earth? 

Oct 23rd, 2017

The centripetal force equals gravity

mv^2/R=mg

v^2=Rg => v=sqrt(Rg)=sqrt(638000 m * 9.81 m/s^2)=2502 m/s = 2.5 km/s

and one trip around the circumference 2*pi*R will take 2*pi*6380/2.5=16034 s = 267 min = 4.45 hours (4 hours and 27 minutes)

Apr 27th, 2015

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