The pressure at depth h is rho*g*h (rho - spec. gravity of water = 1gr/cm^3 , g= 9.81m/s^2, h= 10ft

The force = pressure *Area = rho*g*h*pi*r^2, r = 3ft

Force = (10^(-3)kg/(10^-2 m)^3)*9.81m/s^2*10 (0.3m)*pi*(3*0.3m)^2= 74890 Pa = 74.9 kPa (kilo-pascals)

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