For the reaction, calculate how many grams of the product form when 2.4g
2Mg(s) + O2(g) = 2MgO(s)
Moles of Mg reacting = 2.4/24.3 = 0.098 mole
Hence product formed = 0.098 mole
Mass of product formed
= number of mole*molecular mass of MgO
=3.9494 g ~ 3.95 g
Hence mass of product formed is 3.95 g
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