For the reaction, calculate how many grams of the product form when 2.4g
Na2O(s) + H2O(l) = 2NaOH(aq)
2.4/63 = 0.0380 mole of Na2O was used
mole of NaOH formed = 2 x 0.0380 = 0.076 mol
gram of NaOH = 0.076 x atomic weight of NaOH = 0.076 x 40 = 3.04 g
any clarification plz let me know
how did you get the 63?
63 is a atomic weight of Na2O
that cal be calculated 2 x 23.5 + 16 = 63
and mole = given weight/ molecular weight = 2.4/63
I hope u understood.
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