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Please solve 5 a and 5 b

label Algebra
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Apr 27th, 2015

5(a) Since size is doubled in 13 days

2 = e^(c*13)

=>c = ln2/13 = 0.0533

Hence if for t=0 population = 60000,

equation will be, P = 60000*e^(0.533*t)

Hence population after 3 days = 60000*e^(0.0533*3) 

~ 70403

5(b) In similar condition

Bacteria population will be after 3 days,

P = 60000*e^(((ln 2)/20)*3)

~ 66574 

Apr 27th, 2015

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