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Algebra. Quadratics.

Algebra
Tutor: None Selected Time limit: 0 Hours

Apr 27th, 2015

assume the length of the side of the larger square is x, then the smaller square would have x/2 length 

since Ssmall+Sbig=45 cm^2

thus (x/2)^2+x^2=45 cm^2

(x^2/4)+x^2=45 cm^2

5x^2/4=45 cm^2

5x^2=45*4

x^2=36

x=6

Thus the length of the side of the larger square is 6 cm


Apr 27th, 2015

Thank you.

Apr 27th, 2015

Thank you.

Apr 27th, 2015

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Apr 27th, 2015
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