The size of the old p. lot: 75*300+165*75+75*75=40500

The size of the new p. lot: size of old + x*375+x*(165+75)+x^2

if the size is doubled we must have

40500=375x+240x+x^2

or

x^2+615x-40500=0

the positive root of this equation is: x1 = (-615+sqrt(615^2+4*40500))/2=(-615+sqrt(540775))/2

=(-615+735)/2=60 ft

Thank you.

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