##### Real analysis metric norm questions

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Apr 27th, 2015

we have x , y c E with E on the IR espace vectoriel  d(x,y) is a distance if the three condition are verified :

1. we take x,y c E ; we have d(x,y)= 0  => x=y  the first condition verified

2.  we take x,y c E ; we have d(x,y)= |x|+|y| = |y|+|x|= d(y,x)  the second condition verified

3. we take x,y,z c E ; we have d(x,z) =|x|+|z| =| |x|+|y|-|y|+|z| | <= |x|+|y|+|y|+|z| <= d(x,y) + d(y,z) the third condition virified

So the d(x,y) is a distance in E So E is an espace metric

Good Luck and if need somthing else tell me

Apr 27th, 2015

For some reason i did not write the question down! It was actualy show that d does not make a norm ive been having troble proving that

Apr 27th, 2015

Can you please help me out will rate  this quickly after

Apr 27th, 2015

yes of course ,after how do you find my answer is good  ?

Apr 27th, 2015

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Apr 27th, 2015
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Apr 27th, 2015
Oct 18th, 2017
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