Standard deviation -statistics

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Oct 20th, 2017

In the following problems the normalized score is z = (x – μ)/σ, where μ is the mean and σ is the standard deviation; that is, z = (x – 22.1)/2.3

17. P(20 ≤ x ≤ 24) = P(-0.9130 ≤ z ≤ 0.8261) = 0.6150 or 61.5% (the probability of choosing a student from a given set is equal to the percentage of the students in the set).

18. P(23 < x) = P(0.3913 < z) = 0.3477 or 34.8%

19. P(20.5 < x) =P(-0.6957 < z) = 0.7567 or 75.7%

20. P(x < 25.5) = P( z < 1.4783) = 0.9303 or 93.0%


Apr 27th, 2015

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