The domain of h(x) = 20/(3x^{2} – 48) is given by

Domain is all possible x values. h(x) = 20/3 (x^2 -16) = 20/3 (x+4) (x-4)

Here for x= +4 and x=-4, the function does not exist.

So Domain: All x values except +4 or -4. Mathematically. x not equal to +4 or - 4

Simplified result of the {(3y ^{-2 }z^{2})^{3} ÷ (2x ^{-2 }y z ^{-1})^{2}} with positive exponents is given by

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