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Algebra
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solve by substituting 5x+y=5

                                  9x-4y=-20

Apr 28th, 2015

If we subtract 5x from both sides of the first equation we get:  y = -5x + 5

We can substitute this value of "y" into the second equation:

9x - 4(-5x + 5) = -20

Distribute:  9x + 20x - 20 = -20

29x - 20 = -20;  add 20 to both sides

29x = 0;  x = 0

Substitute 0 in for x in one of the equations and we get: y = -5(0) + 5

y = 5

x=0, y=5

Apr 27th, 2015

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