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will best answer! need urgent help! chem! easy! 2 parts!

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Apr 28th, 2015

Mg(OH)2 = Mg+ + 2OH-

Ksp = [Mg+] [OH-]2

5.6*10-12= [x] [x]2

X3 = 5.6*10-12

X = 0.0001 mol/L

Mol of Mg(OH)2 = mass of Mg(OH)2/ molecular mass of Mg(OH)2

Mass of Mg(OH)2= 0.0001* 58.305

  = 0.0058 g/L

Part (b):

pH + pOH = 14

pOH = 14-10

pOH = 4

pOH = -log[OH-]

[OH-]=antilog- 4

[OH-]=0.0001 M

2 OH- produces by 1 Mg(OH)2

0.0001mol OH- produces by( 1*0.0001)/2

  = 0.00005mol/L

Mass of Mg(OH)2= mol of Mg(OH)2 * molecular mass of Mg(OH)2

  = 0.00005 * 58.305

  =0.00291g/L


Apr 28th, 2015

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