y= - 3/s

[-3,-1]

Divide the interval into four parts:

-3 <= s <= -2.5, the right end is s_1 = -2.5

-2.5 <= s <= -2, the right end is s_2 = -2

-2 <= s <= -1.5, the right end is s_3 = -1.5

-1.5 <= s <= -1, the right end is s_4 = -1

Write the sum of the areas of the four rectangles

y(s_1)(-2.5 - (-3)) + y(s_2)(-2 - (-2.5)) + y(s_3)(-1.5 - (-2)) + y(s_4)(-1 - (-1.5)) =

(1/2)[ -3/-2.5 + -3/-2 + -3/-1.5 + -3/-1 ] = (1/2) (1.2 + 1.5 + 2 + 3) = 7.7/2 = 3.85.

This sum may be used as an approximate value of the area under the graph of y(s) on the interval -3<s<-1.

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