Suppose z varies jointly as y and the cube of x. If z=168 when x=2 and y=7, what is z when x=10 and y=4
the statement, z = kx3y,
where k is a constant. Set x = 2, y = 7, and z = 168. Then 168 = k·23·7 = 56k,
and k = 3. Finally, if x = 10 and y = 4, then z = 3·103·4
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