From
the statement, z = kx^{3}y,
where k is a constant. Set x = 2, y = 7, and z = 168. Then 168 = k·2^{3}·7 = 56k,
and k = 3. Finally, if x = 10 and y = 4, then z = 3·10^{3}·4
= 12000.

Apr 28th, 2015

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