how do write an equation of a line that passes through (8,4) and has an y- intercept of 6?
If the line has a y-intercept of 6, that is the point (0,6); that along with the other point (8,4), allows us to find the slope using the slope formula:
(4-6)/(8-0) = -2/8 = -1/4
So now we can put it in slope-intercept form:
y = -1/4 x + 6
Hope that helps.
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