F(x)= intergal (bottom) to (top) as x goes to x^2
sec^2 t dt
so the integral of sec^2 tdt = tant
That isn't one of the answer choices
Its more detailed I believe
I believe you know have to plug in what the integral goes to
please clarify what integral goes from i am not able to get it....is it from x to x^2
answer should be A)
Can you show how you got this answer? I need to know how to work the problem
the answer of integral is
(tant) from x to x^2
i e tanx^2-tanx
now we have to differentiate the function tanx^2- tanx
now we will get,
so answer is B sorry for mistake.
did u get????
Can you break down your derivative steps
d/dt(tanx^2-tanx)= d/dt(tan(x^2))-d/dt(tanx) but we know that d/dt(tanx)=sec^2 (x)
so = sec^2(x^2) .d/dt(x^2) -sec^2(x) ( use chain rule of derivative)
=2x.sec(x^2).sec(x^2) - secx.secx
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