I need help with finding the cennter and radius of a circle

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x^2+y^2-16x+18y=-141 a) (-8,9),r=4 , B) (9,-8), r=4 , C). (8,-9), r=2, D). (-9,8), r=2 which choice is it?

Apr 28th, 2015

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Apr 28th, 2015

x^2+y^2-16x+18y=-141 

x^2+y^2-16x+18y+141 =0

x^2-16x+y^2+18y+141 =0

Convert the above to the form (x+a)^2 to (y+b)^2 = r^2

so the center will be (-a, -b).

so the above equation becomes

x^2-16x+64-64 +y^2+18y+81-81+141 =0

x^2-16x+64+y^2+18y+81-64-81+141 =0

(x-8)^2 + (y+9)^2 -145 +141 =0

(x-8)^2 + (y+9)^2 -4 =0

(x-8)^2 + (y+9)^2 =4

so the center is (8, -9).

Please let me know if you have any other questions and best me if you are satisfactory.

Apr 28th, 2015

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