A woman made a deposit of $291. If her deposit consisted of 83 bills, some of them one-dollar bills and the rest being five-dollar bills, how many one-dollar bills did she deposit?
Let no: of one-dollar bills be 'x' and no: of five-dollar
bills be 'y'
so total money = 291 = 1*x+5 *y = x + 5y
x + 5y =291
Subtract equation 2 from 1,4y = 291-83 =208
so y = 208/4 =52So Substituting 'y' in eq.2 we get,x+52 =83
x = 31
So no: of one-dollar bills is 31 and no: of five-dollar
bills be 52
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