The best way to think about these problems is to remember what happens when you have x^-1. This is the same thing 1/x. Technically speaking x^-1 is the same as (x^1)^-1. So think about it like we put 1 x^1 in the denominator. Now if we look at this problem it has (x^3)^-5. So we would multiply 5 x^3 in the denominator and get 1/x^15. Hope this helps. Feel free to message me with any other questions
Apr 28th, 2015
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