For a certain reaction, ΔH° = –72.8 kJ and ΔS° = –227 J/K. If n = 2, calculate ε° for the reaction at 25°C.
ΔG= ΔH -T ΔS
ΔG= -nFE = ΔH -T ΔS
E = (ΔH -T ΔS)/-nF
( -72800J+ 25 *227J) / (-96500 *2)
E= 0.35 V
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