A particle moves along a horizontal line. Its position function is s(t)

Calculus
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A particle moves along a horizontal line. Its position function is s(t) for t> less than or equal to 0. Find the displacement of the particle and the distance traveled by the particle over the given interval.

s(t)=t^3-22t^2+105t; 0less than or equal to<t less than or equal to <9

Displacement =

Distance traveled=

Apr 29th, 2015

s(9) = 9^3 - 22(9^2) + 105(9) = -108

therefore the displacement is

sqrt((9-0)^2 + (-108 -0)^2 = 108.37

The distance along the curve is given by

the integral of sqrt(1 + (dy/dx)^2)  from 0 to 9

dy/dx = 3t^2 -44t + 105

integral of sqrt(3t^2 - 44t + 106) from 0 t0 9

If you can give me a little more time I'll work out the integral for you

Apr 29th, 2015

Its okay

Apr 29th, 2015

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