Quadratic Function Fixed Points

label Calculus
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Give a quadratic function whose fixed points are x = −5 and x = 6.

Apr 29th, 2015

Quadratic function is of the type Ax^2+Bx+C

we have x=-5  and x=6

therefore,

Quadratic function is

(x+5)(x-6)=0

solving,

x^2-6x+5x-30=0

x^2-x-30=0

is the required Quadratic function.

Apr 29th, 2015

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