please help me with these question

User Generated

npvq

Science

Description

A 10.0-mL sample of pineapple juice was titrated with 0.100 M sodium hydroxide solution. the average volume of NaOH required to reach the endpoint was 12.8 mL


a.Calculate the number of moles of sodium hydroxide required to reach the endpoint


answer:


b.Using the mole ratio for the neutralization reaction shown in equation 1, determine the number of moles of citric acid in 10.0 mL of the of pineapple juice.

User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.

Explanation & Answer

DATA:

Volume of citric acid= 10.0mL

Concentration of NAOH= 0.1M

Volume of NaOH= 12.8mL

Moles of NaOH at end point= ?

Moles of citric acid/10.0mL= ?

SOLUTION:

C6H8O7 + 3NaOH è Na3C6H5O7 + 3H2O

MOLES OF NaOH:

1000.0mL of NaOH contains 0.1 mol Of NaOH

12.8mL of NaOH contains (0.1*12.8)/1000

  =1.28*10-3 mol of NaOH

MOLES OF CITRIC ACID:

3NaOH = 1 C6H8O7

1.28*10-3 = (1*1.28*10-3)/3

  = 4.2666*10-4 mol of C6H8O7/10.0mL

ANSWER:

Moles of NaOH at end point= 1.28*10-3 mol of NaOH

Moles of citric acid/10.0mL=4.2666*10-4 mol of C6H8O7



Anonymous
I was struggling with this subject, and this helped me a ton!

Studypool
4.7
Trustpilot
4.5
Sitejabber
4.4

Similar Content

Related Tags