please help me with these question

label Chemistry
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

A 10.0-mL sample of pineapple juice was titrated with 0.100 M sodium hydroxide solution. the average volume of NaOH required to reach the endpoint was 12.8 mL


a.Calculate the number of moles of sodium hydroxide required to reach the endpoint


answer:


b.Using the mole ratio for the neutralization reaction shown in equation 1, determine the number of moles of citric acid in 10.0 mL of the of pineapple juice.

Apr 29th, 2015

DATA:

Volume of citric acid= 10.0mL

Concentration of NAOH= 0.1M

Volume of NaOH= 12.8mL

Moles of NaOH at end point= ?

Moles of citric acid/10.0mL= ?

SOLUTION:

C6H8O7 + 3NaOH รจ Na3C6H5O7 + 3H2O

MOLES OF NaOH:

1000.0mL of NaOH contains 0.1 mol Of NaOH

12.8mL of NaOH contains (0.1*12.8)/1000

  =1.28*10-3 mol of NaOH

MOLES OF CITRIC ACID:

3NaOH = 1 C6H8O7

1.28*10-3 = (1*1.28*10-3)/3

  = 4.2666*10-4 mol of C6H8O7/10.0mL

ANSWER:

Moles of NaOH at end point= 1.28*10-3 mol of NaOH

Moles of citric acid/10.0mL=4.2666*10-4 mol of C6H8O7


Apr 29th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Apr 29th, 2015
...
Apr 29th, 2015
Jun 24th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer