the solubility of lead (ii) chloride (pbcl2) is 10.85 g/L. calculate the solubil

Chemistry
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the solubility of lead (ii) chloride (pbcl2) is 10.85 g/L. calculate the solubility product for pbcl2

Apr 29th, 2015

DATA:

Solubility of PbCl2= 10.85g/L

Ksp of PbCl2 =?

SOLUTION:

PbCl2 = Pb2+ + 2Cl-

Mol of PbCl2 = mass of PbCl2/ molecular mass of PbCl2

  = 10.85/ 278.1

  =0.0390mol/L

Ksp = [ Pb2+] [Cl-]2

  = [.0390] [.0390]2

  =5.9319*10-5 M2/L2


Apr 29th, 2015

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Apr 29th, 2015
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Apr 29th, 2015
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