What do I do with the -3 exponent in the problem?
(14−a0 b2 ) −3
The question is not clear.... Can you please post the full question?
Sorry I thought it went threw
The Question is (14-a^0 b^2)^-3 a=-2 and b=4
What do I do with the -3 exponent on the outside?
b^2 = 4^2 =16
(14-a^0 b^2)^-3 = (14-16)^-3
= (-2)^0/ (-2)^3
Please let me know if you have any other questions and best me if you are satisfactory.
Sorry im confused i guess it is how it i set up, can you show in pdf? Also I really need to know what you did with the -3. Sorry for the hastle. :/
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