a=-2 b=4

What do I do with the -3 exponent in the problem?

(14−a0 b2 ) −3

The question is not clear.... Can you please post the full question?

Sorry I thought it went threw

The Question is (14-a^0 b^2)^-3 a=-2 and b=4

What do I do with the -3 exponent on the outside?

a^0 =1

b^2 = 4^2 =16

(14-a^0 b^2)^-3 = (14-16)^-3

= (-2)^-3

=(-2)^0-3

= (-2)^0/ (-2)^3

= 1/(-2)^3

= -1/8

Please let me know if you have any other questions and best me if you are satisfactory.

Sorry im confused i guess it is how it i set up, can you show in pdf? Also I really need to know what you did with the -3. Sorry for the hastle. :/

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