one chem question, need help :) thank you

label Chemistry
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

Apr 29th, 2015

This is a buffer problem. 

ICE table should be used 

Ka = 2.0 x 10^-9 = [H+][OBr-] / [HOBr] 

0.50 mol in 1.00 L = 0.50 M HOBr 
0.30 mol in 1.00 L = 0.30 M KOBr (or OBr-) 

HOBr + H2O <-> H3O+ + OBr- 
0.50                       0           0.30 
-x +x +x 
(0.50-x)   x   (0.30+x) 

Assume x is small comparing to 0.30 and 0.50 

2.0 x 10^-9 = x (0.30) / 0.50) 

[H3O+] = x = 3.33 x 10^-9 

So : 
pH = 8.48


Good Luck 

Apr 29th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Apr 29th, 2015
...
Apr 29th, 2015
Jun 25th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer