Find a solution to the following system of equations.

label Mathematics
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5


Find a solution to the following system of equations.

- 2 x + y = - 3

- x + 2 y = - 3

a.  (–3, –9)

b.  (–21, –9)

c.  (3, 3)

d.  (0, 2)

Apr 29th, 2015

- 2 x + y = - 3

- x + 2 y = - 3

To eliminate y, multiply  eq.1 by 2  

- 4 x + 2y = - 6

- x + 2 y = - 3

Subtract  equation 2  from 3,

-3x = -3

 x=1
So y = -3 +2 = -1

The points are (1,-1).

Please check if the equations are correct.


Apr 29th, 2015

the second equation is  - x + 2 y = 3 

Apr 29th, 2015

- 2 x + y = - 3

- x + 2 y = 3

To eliminate y, multiply  eq.1 by 2 

- 4 x + 2y = - 6

- x + 2 y = 3

Subtract  equation 2  from 3,

-3x = -9

 x=3
So y = -3 +6 = 3

The points are (3,3).



Please let me know if you have any other questions and best me if you are satisfactory. 


Apr 29th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Apr 29th, 2015
...
Apr 29th, 2015
Jun 29th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer