in ΔDEF, FE = 5 and m<D=43 Find DE to the nearest tenth.

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a.8.6

b.5.4

c.9.3

d.15.1

The side FE is opposite to the angle <D in the right triangle ∆DEF while DE is the adjacent side.

Thus, FE / DE = tan<D and DE = FE cot<D = 5 / tan 43° = 5/0.93 = 5.4 and the answer is B.

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