Description
User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.
Explanation & Answer
1, 2, 3, 4 are all correct.............barring 5.
Completion Status:
100%
Review
Review
Anonymous
Awesome! Perfect study aid.
Studypool
4.7
Trustpilot
4.5
Sitejabber
4.4
24/7 Homework Help
Stuck on a homework question? Our verified tutors can answer all questions, from basic math to advanced rocket science!
Most Popular Content
Los Angeles Valley College Exploring Relationship Between Two Variables Report
You will search for two quantitative variables that may have a linear correlation. You will describe and analyze the relat ...
Los Angeles Valley College Exploring Relationship Between Two Variables Report
You will search for two quantitative variables that may have a linear correlation. You will describe and analyze the relationship between the variables.
Using these data, construct limits for x- and R- charts.
Small boxes of NutraFlakes cereal are labeled “net weight 10 ounces.” Each hour, random samples of size n = 4 boxes ar ...
Using these data, construct limits for x- and R- charts.
Small boxes of NutraFlakes cereal are labeled “net weight 10 ounces.” Each hour, random samples of size n = 4 boxes are weighed to check process control. Five hours of observations yielded the following: Weight Time Box 1 Box 2 Box 3 Box 4 9 A.M. 9.8 10.4 9.9 10.3 10 A.M. 10.1 10.2 9.9 9.8 11 A.M. 9.9 10.5 10.3 10.1 Noon 9.7 9.8 10.3 10.2 1 P.M. 9.7 10.1 9.9 9.9 Using these data, construct limits for x- and R- charts. Is the process in control? What other steps should the QC department follow at this point?
STAT2002 Walden Null and Alternative Hypotheses and Type I and Type II Errors HW
In this Discussion, you will locate an article or news story where the author presents statistics as evidence and will con ...
STAT2002 Walden Null and Alternative Hypotheses and Type I and Type II Errors HW
In this Discussion, you will locate an article or news story where the author presents statistics as evidence and will consider the impact of understanding the null hypotheses, type I errors, and type II errors.To prepare for this Discussion: Review this week’s Learning Resources.Find a news story in which the author(s) presents statistics as evidence. Consider the following questions:What is the author(s) trying to prove? In other words, what question is the author(s) trying to answer?What would the null hypothesis be?What would happen if the author(s) rejected the null?What action would the author(s) take?If there were a type I error, what would be the effect of the action taken?What would happen if the author(s) could not reject the null?What action would the author(s) take?If there were a type II error, what would be the effect of the action?Review the Academic Writing Expectations for 2000/3000-Level Courses, provided in this week’s Learning Resources.Assignment: Post a 150- to 225-word (2- to 3-paragraph) explanation of the role of null and alternative hypotheses as well as type I and II errors in situations where people use statistics as evidence. In your explanation, address the following:Identify, briefly, the null and alternative hypotheses involved in the news story you located, as well as explain what the author(s) is trying to prove.Describe what the implications might be if the author(s) rejected the null and if the author(s) could not reject the null.Explain the impact of potential type I and/or type II errors.To support your response, be sure to reference at least one properly cited scholarly source.
American Military University Statistics Confidence Intervals and Sample Size Quiz
Question 1 (1 point) The population standard deviation for the height of college basketball players is 3 inches. If we wan ...
American Military University Statistics Confidence Intervals and Sample Size Quiz
Question 1 (1 point) The population standard deviation for the height of college basketball players is 3 inches. If we want to estimate a 99% confidence interval for the population mean height of these players with a 0.5 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer:Question 2 (1 point) Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was estimated that the current proportion of customers who click on ads on their smartphones is 0.68. How many customers should the company survey in order to be 97% confident that the margin of error is 0.29 for the confidence interval of true proportion of customers who click on ads on their smartphones? Answer: (Round up your answer to nearest whole number)Question 3 (1 point) Select the correct answer for the blank: If everything else stays the same, the required sample size ____ as the confidence level increases to reach the same margin of error. Answer:IncreasesDecreasesRemains the sameQuestion 4 (1 point) Select the correct answer for the blank: If everything else stays the same, the required sample size ____ as the confidence level decreases to reach the same margin of error. Answer:IncreasesDecreasesRemains the sameQuestion 5 (1 point) The population standard deviation for the height of college basketball players is 3.5 inches. If we want to estimate 97% confidence interval for the population mean height of these players with a 0.5 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer:Question 6 (1 point) The population standard deviation for the height of college basketball players is 3 inches. If we want to estimate 97% confidence interval for the population mean height of these players with a 0.6 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer:Question 7 (1 point) There is no prior information about the proportion of Americans who support gun control in 2018. If we want to estimate 92% confidence interval for the true proportion of Americans who support gun control in 2018 with a 0.2 margin of error, how many randomly selected Americans must be surveyed? Answer: (Round up your answer to nearest whole number)Question 8 (1 point) A random sample found that forty percent of 100 Americans were satisfied with the gun control laws in 2017. Compute a 99% confidence interval for the true proportion of Americans who were satisfied with the gun control laws in 2017. Fill in the blanks appropriately.A 99% confidence interval for the true proportion of Americans who were satisfied with the gun control laws in 2017 is () (round to 3 decimal places)Question 9 (1 point) In a random sample of 80 people, 52 consider themselves as baseball fans. Compute a 95% confidence interval for the true proportion of people consider themselves as baseball fans and fill in the blanks appropriately.We are 95% confident that the true proportion of people consider themselves as baseball fans is betweenand. (round to 3 decimal places)Question 10 (1 point) A random sample of 150 people was selected and 12% of them were left handed. Find the 90% confidence interval for the proportion of left-handed people.(0.0436, 0.1164)(0.068, 0.172)(.12, .88)(–1.645, 1.645)(0.0764, 0.1636)Question 11 (1 point) Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was estimated that the current proportion of customers who click on ads on their smartphones is 0.42 based on a random sample of 100 customers.Compute a 92% confidence interval for the true proportion of customers who click on ads on their smartphones and fill in the blanks appropriately.< p <(round to 3 decimal places)Question 12 (1 point) Suppose you compute a confidence interval with a sample size of 25. What will happen to the confidence interval if the sample size increases to 50?Get largerNothingGet smallerQuestion 13 (1 point) The percent defective for parts produced by a manufacturing process is targeted at 4%. The process is monitored daily by taking samples of sizes n = 160 units. Suppose that today's sample contains 14 defectives.How many units would have to be sampled to be 95% confident that you can estimate the fraction of defective parts within 2% (using the information from today's sample--that is using the result that p̂=0.0875)?Place your answer, as a whole number, in the blank. For example, 567 would be a legitimate entry.Question 15 (1 point) A sample of 9 production managers with over 15 years of experience has an average salary of $71,000 and a sample standard deviation of $18,000.Assuming that the salaries of production managers with over 15 years experience are normally distributed, you can be 95% confident that the mean salary for all production managers with at least 15 years of experience is between what two numbers.Place your LOWER limit, rounded to a whole number, in the first blank. Do not use a dollar sign, a comma, or any other stray mark. For example, 54321 would be a legitimate entry.___. Place your UPPER limit, rounded to a whole number, in the second blank. Do not use a dollar sign, a comma, or any other stray mark. For example, 65432 would be a legitimate entry.___Answer # 1 Answer # 2 Question 16 (1 point) After calculating the sample size needed to estimate a population proportion to within 0.05, you have been told that the maximum allowable error (E) must be reduced to just 0.025. If the original calculation led to a sample size of 1000, the sample size will now have to be___.Place your answer, as a whole number in the blank. For example, 2345 would be a legitimate entry.Question 18 (1 point) A random sample of college football players had an average height of 64.55 inches. Based on this sample, (63.2, 65.9) found to be a 92% confidence interval for the population mean height of college football players. Select the correct answer to interpret this interval.-We are 92% confident that the population mean height of college football players is between 63.2 and 65.9 inches.-We are 92% confident that the population mean height of college football palyers is 64.55 inches.-A 92% of college football players have height between 63.2 and 65.9 inches.-There is a 92% chance that the population mean height of college football players is between 63.2 and 65.9 inches.Question 20 (1 point) A random sample of college football players had an average height of 66.35 inches. Based on this sample, (65.6, 67.1) found to be a 90% confidence interval for the population mean height of college football players. Select the correct answer to interpret this interval.-We are 90% confident that the population mean height of college football players is between 65.6 and 67.1 inches.-There is a 90% chance that the population mean height of college football players is between 65.6 and 67.1 inches.-We are 90% confident that the population mean height of college football palyers is 66.35 inches.-A 90% of college football players have height between 65.6 and 67.1 inches.
Similar Content
Suficient Statistic Determination Independent Random Variables Solved Practice
Please help me finish this in 4 hours, Thank you so much......,.,,,,,,,...
69-71.Use the given calculations to write 3 new essays. 1 page for each.
Use the given calculations to write 3 new essays. 1 page for each.Please note that they are 3 individual essay, you need t...
word problem for mathematics
...
MSC 300 Catholic University of America Business Statistics Budget Exercise Excel Worksheet
Download this excel sheet.MSC 300-Midterm SU2020Updated.xlsxSolve the three cases as instructed and upload the solution he...
BHS Solve the Equation
Solve the equation for b,
Answer A. Negative two
Answer B. Negative three
Answer C. No solution
Answer D. Three
 ...
Central Georgia Technical College Algebra Domain and Range on Graph Question
12 of 20 (14 complete)
Ay
10
Use the graph to determine the following
a. the function's domain
b. the function's range
c. ...
Week1solutions Final
Question: Raffle: Five hundred people attend a charity event, and each buys a raffle ticket. The 500 ticket stubs are put ...
Final Answer
...
20201026233159quality Control Exercise
Problems with the quantity of candy in the package. The best way to properly assure the quality in a CTQ of the product is...
Related Tags
Book Guides
Nervous Conditions
by Tsitsi Dangarembga
The Good Earth
by Pearl S. Buck
Animal Farm
by George Orwell
Heart of Darkness
by Joseph Conrad
Too Much and Never Enough
by Mary L. Trump
Slaughterhouse Five
by Kurt Vonnegut
The Joy Luck Club
by Amy Tan
Don Quixote
by Miguel de Cervantes
Tess of the DUrbervilles
by Thomas Hardy
Get 24/7
Homework help
Our tutors provide high quality explanations & answers.
Post question
Most Popular Content
Los Angeles Valley College Exploring Relationship Between Two Variables Report
You will search for two quantitative variables that may have a linear correlation. You will describe and analyze the relat ...
Los Angeles Valley College Exploring Relationship Between Two Variables Report
You will search for two quantitative variables that may have a linear correlation. You will describe and analyze the relationship between the variables.
Using these data, construct limits for x- and R- charts.
Small boxes of NutraFlakes cereal are labeled “net weight 10 ounces.” Each hour, random samples of size n = 4 boxes ar ...
Using these data, construct limits for x- and R- charts.
Small boxes of NutraFlakes cereal are labeled “net weight 10 ounces.” Each hour, random samples of size n = 4 boxes are weighed to check process control. Five hours of observations yielded the following: Weight Time Box 1 Box 2 Box 3 Box 4 9 A.M. 9.8 10.4 9.9 10.3 10 A.M. 10.1 10.2 9.9 9.8 11 A.M. 9.9 10.5 10.3 10.1 Noon 9.7 9.8 10.3 10.2 1 P.M. 9.7 10.1 9.9 9.9 Using these data, construct limits for x- and R- charts. Is the process in control? What other steps should the QC department follow at this point?
STAT2002 Walden Null and Alternative Hypotheses and Type I and Type II Errors HW
In this Discussion, you will locate an article or news story where the author presents statistics as evidence and will con ...
STAT2002 Walden Null and Alternative Hypotheses and Type I and Type II Errors HW
In this Discussion, you will locate an article or news story where the author presents statistics as evidence and will consider the impact of understanding the null hypotheses, type I errors, and type II errors.To prepare for this Discussion: Review this week’s Learning Resources.Find a news story in which the author(s) presents statistics as evidence. Consider the following questions:What is the author(s) trying to prove? In other words, what question is the author(s) trying to answer?What would the null hypothesis be?What would happen if the author(s) rejected the null?What action would the author(s) take?If there were a type I error, what would be the effect of the action taken?What would happen if the author(s) could not reject the null?What action would the author(s) take?If there were a type II error, what would be the effect of the action?Review the Academic Writing Expectations for 2000/3000-Level Courses, provided in this week’s Learning Resources.Assignment: Post a 150- to 225-word (2- to 3-paragraph) explanation of the role of null and alternative hypotheses as well as type I and II errors in situations where people use statistics as evidence. In your explanation, address the following:Identify, briefly, the null and alternative hypotheses involved in the news story you located, as well as explain what the author(s) is trying to prove.Describe what the implications might be if the author(s) rejected the null and if the author(s) could not reject the null.Explain the impact of potential type I and/or type II errors.To support your response, be sure to reference at least one properly cited scholarly source.
American Military University Statistics Confidence Intervals and Sample Size Quiz
Question 1 (1 point) The population standard deviation for the height of college basketball players is 3 inches. If we wan ...
American Military University Statistics Confidence Intervals and Sample Size Quiz
Question 1 (1 point) The population standard deviation for the height of college basketball players is 3 inches. If we want to estimate a 99% confidence interval for the population mean height of these players with a 0.5 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer:Question 2 (1 point) Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was estimated that the current proportion of customers who click on ads on their smartphones is 0.68. How many customers should the company survey in order to be 97% confident that the margin of error is 0.29 for the confidence interval of true proportion of customers who click on ads on their smartphones? Answer: (Round up your answer to nearest whole number)Question 3 (1 point) Select the correct answer for the blank: If everything else stays the same, the required sample size ____ as the confidence level increases to reach the same margin of error. Answer:IncreasesDecreasesRemains the sameQuestion 4 (1 point) Select the correct answer for the blank: If everything else stays the same, the required sample size ____ as the confidence level decreases to reach the same margin of error. Answer:IncreasesDecreasesRemains the sameQuestion 5 (1 point) The population standard deviation for the height of college basketball players is 3.5 inches. If we want to estimate 97% confidence interval for the population mean height of these players with a 0.5 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer:Question 6 (1 point) The population standard deviation for the height of college basketball players is 3 inches. If we want to estimate 97% confidence interval for the population mean height of these players with a 0.6 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer:Question 7 (1 point) There is no prior information about the proportion of Americans who support gun control in 2018. If we want to estimate 92% confidence interval for the true proportion of Americans who support gun control in 2018 with a 0.2 margin of error, how many randomly selected Americans must be surveyed? Answer: (Round up your answer to nearest whole number)Question 8 (1 point) A random sample found that forty percent of 100 Americans were satisfied with the gun control laws in 2017. Compute a 99% confidence interval for the true proportion of Americans who were satisfied with the gun control laws in 2017. Fill in the blanks appropriately.A 99% confidence interval for the true proportion of Americans who were satisfied with the gun control laws in 2017 is () (round to 3 decimal places)Question 9 (1 point) In a random sample of 80 people, 52 consider themselves as baseball fans. Compute a 95% confidence interval for the true proportion of people consider themselves as baseball fans and fill in the blanks appropriately.We are 95% confident that the true proportion of people consider themselves as baseball fans is betweenand. (round to 3 decimal places)Question 10 (1 point) A random sample of 150 people was selected and 12% of them were left handed. Find the 90% confidence interval for the proportion of left-handed people.(0.0436, 0.1164)(0.068, 0.172)(.12, .88)(–1.645, 1.645)(0.0764, 0.1636)Question 11 (1 point) Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was estimated that the current proportion of customers who click on ads on their smartphones is 0.42 based on a random sample of 100 customers.Compute a 92% confidence interval for the true proportion of customers who click on ads on their smartphones and fill in the blanks appropriately.< p <(round to 3 decimal places)Question 12 (1 point) Suppose you compute a confidence interval with a sample size of 25. What will happen to the confidence interval if the sample size increases to 50?Get largerNothingGet smallerQuestion 13 (1 point) The percent defective for parts produced by a manufacturing process is targeted at 4%. The process is monitored daily by taking samples of sizes n = 160 units. Suppose that today's sample contains 14 defectives.How many units would have to be sampled to be 95% confident that you can estimate the fraction of defective parts within 2% (using the information from today's sample--that is using the result that p̂=0.0875)?Place your answer, as a whole number, in the blank. For example, 567 would be a legitimate entry.Question 15 (1 point) A sample of 9 production managers with over 15 years of experience has an average salary of $71,000 and a sample standard deviation of $18,000.Assuming that the salaries of production managers with over 15 years experience are normally distributed, you can be 95% confident that the mean salary for all production managers with at least 15 years of experience is between what two numbers.Place your LOWER limit, rounded to a whole number, in the first blank. Do not use a dollar sign, a comma, or any other stray mark. For example, 54321 would be a legitimate entry.___. Place your UPPER limit, rounded to a whole number, in the second blank. Do not use a dollar sign, a comma, or any other stray mark. For example, 65432 would be a legitimate entry.___Answer # 1 Answer # 2 Question 16 (1 point) After calculating the sample size needed to estimate a population proportion to within 0.05, you have been told that the maximum allowable error (E) must be reduced to just 0.025. If the original calculation led to a sample size of 1000, the sample size will now have to be___.Place your answer, as a whole number in the blank. For example, 2345 would be a legitimate entry.Question 18 (1 point) A random sample of college football players had an average height of 64.55 inches. Based on this sample, (63.2, 65.9) found to be a 92% confidence interval for the population mean height of college football players. Select the correct answer to interpret this interval.-We are 92% confident that the population mean height of college football players is between 63.2 and 65.9 inches.-We are 92% confident that the population mean height of college football palyers is 64.55 inches.-A 92% of college football players have height between 63.2 and 65.9 inches.-There is a 92% chance that the population mean height of college football players is between 63.2 and 65.9 inches.Question 20 (1 point) A random sample of college football players had an average height of 66.35 inches. Based on this sample, (65.6, 67.1) found to be a 90% confidence interval for the population mean height of college football players. Select the correct answer to interpret this interval.-We are 90% confident that the population mean height of college football players is between 65.6 and 67.1 inches.-There is a 90% chance that the population mean height of college football players is between 65.6 and 67.1 inches.-We are 90% confident that the population mean height of college football palyers is 66.35 inches.-A 90% of college football players have height between 65.6 and 67.1 inches.
Earn money selling
your Study Documents